\(\tan^{-1}x+\cot^{-1}x\) का मान क्या है, जहाँ (x>0)?
What is \(\tan^{-1}x+\cot^{-1}x\), where (x>0)?
Explanation opens after your attempt
B. \(\frac{\pi}{2}\)
Concept
For positive (x), \(\tan^{-1}x+\cot^{-1}x=\frac{\pi}{2}\). Be careful when the sign changes.
Why this answer is correct
The correct answer is B. \(\frac{\pi}{2}\). For positive (x), \(\tan^{-1}x+\cot^{-1}x=\frac{\pi}{2}\). Be careful when the sign changes.
Exam Tip
धनात्मक (x) के लिए \(\tan^{-1}x+\cot^{-1}x=\frac{\pi}{2}\) होता है। चिह्न बदलने पर सावधानी रखें।
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