यदि (x>0) हो तो \(\tan^{-1}x+\cot^{-1}x\) का मान क्या है?

If (x>0), what is the value of \(\tan^{-1}x+\cot^{-1}x\)?

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

A. \(\frac{\pi}{2}\)

Step 1

Concept

When (x>0), \(\tan^{-1}x+\cot^{-1}x=\frac{\pi}{2}\). Keep the principal range of \(\cot^{-1}x\) in mind.

Step 2

Why this answer is correct

The correct answer is A. \(\frac{\pi}{2}\). When (x>0), \(\tan^{-1}x+\cot^{-1}x=\frac{\pi}{2}\). Keep the principal range of \(\cot^{-1}x\) in mind.

Step 3

Exam Tip

जब (x>0) हो तो \(\tan^{-1}x+\cot^{-1}x=\frac{\pi}{2}\) होता है। \(\cot^{-1}x\) की प्रधान सीमा का ध्यान रखें।

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FAQs

Mathematics Answer, Explanation and Revision Hints

यदि (x>0) हो तो \(\tan^{-1}x+\cot^{-1}x\) का मान क्या है? / If (x>0), what is the value of \(\tan^{-1}x+\cot^{-1}x\)?

Correct Answer: A. \(\frac{\pi}{2}\). Explanation: जब (x>0) हो तो \(\tan^{-1}x+\cot^{-1}x=\frac{\pi}{2}\) होता है। \(\cot^{-1}x\) की प्रधान सीमा का ध्यान रखें। / When (x>0), \(\tan^{-1}x+\cot^{-1}x=\frac{\pi}{2}\). Keep the principal range of \(\cot^{-1}x\) in mind.

Which concept should I revise for this Mathematics MCQ?

When (x>0), \(\tan^{-1}x+\cot^{-1}x=\frac{\pi}{2}\). Keep the principal range of \(\cot^{-1}x\) in mind.

What exam hint can help solve this Mathematics question?

जब (x>0) हो तो \(\tan^{-1}x+\cot^{-1}x=\frac{\pi}{2}\) होता है। \(\cot^{-1}x\) की प्रधान सीमा का ध्यान रखें।