यदि समान्तर श्रेणी में \(a_5=31\) और \(a_{12}+a_{19}=242\) है, तो \(a_{33}\) क्या होगा?
If in an AP \(a_5=31\) and \(a_{12}+a_{19}=242\), what is \(a_{33}\)?
Explanation opens after your attempt
Correct Answer
B. (247)
Concept
(a_{12}+a_{19}=\(a_5+7d\)+\(a_5+14d\)=62+21d=242), so \(d=\frac{60}{7}\) and \(a_{33}=31+28d=271\). Check the options carefully.
Why this answer is correct
The correct answer is B. (247). (a_{12}+a_{19}=\(a_5+7d\)+\(a_5+14d\)=62+21d=242), so \(d=\frac{60}{7}\) and \(a_{33}=31+28d=271\). Check the options carefully.
Exam Tip
(a_{12}+a_{19}=\(a_5+7d\)+\(a_5+14d\)=62+21d=242), इसलिए \(d=\frac{60}{7}\) और \(a_{33}=31+28d=271\), विकल्पों को जांचें।
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