समीकरण (9x-2-6(k-1)x+(k-1)2=0) के मूलों की प्रकृति क्या है?
What is the nature of roots of (9x-2-6(k-1)x+(k-1)2=0)?
Explanation opens after your attempt
Correct Answer
A. हमेशा वास्तविक और समानAlways real and equal
Concept
Here (D=[-6(k-1)]2-4(9)(k-1)2=0). Hence roots are real and equal for every (k).
Why this answer is correct
The correct answer is A. हमेशा वास्तविक और समान / Always real and equal. Here (D=[-6(k-1)]2-4(9)(k-1)2=0). Hence roots are real and equal for every (k).
Exam Tip
यहाँ (D=[-6(k-1)]2-4(9)(k-1)2=0) है। अतः हर (k) के लिए मूल वास्तविक और समान हैं।
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