Concept-wise Practice

algebraic surds MCQ Questions for Class 10

algebraic surds se related questions ko ek jagah revise karein. Har question me bilingual content, answer feedback aur explanation available hai.

All Tags Search Similar

Practice Questions

3 questions tagged with algebraic surds.

Question 1/3 Expert Mathematics Real Numbers Irrational numbers Class 10 Level 14

यदि \(a=3+\sqrt{5}\), तो \(a^2-6a\) का मान क्या है?

If \(a=3+\sqrt{5}\), what is the value of \(a^2-6a\)?

Explanation opens after your attempt
Correct Answer

A. (-4)

Step 1

Concept

(a-2-6a=a(a-6)).

Step 2

Why this answer is correct

\(a-6=\sqrt{5}-3\), so (a(a-6)=\(3+\sqrt{5}\)\(\sqrt{5}-3\)=5-9=-4).

Step 3

Exam Tip

Recognize the hidden conjugate form. चरण 1: (a-2-6a=a(a-6)) है। चरण 2: \(a-6=\sqrt{5}-3\), इसलिए (a(a-6)=\(3+\sqrt{5}\)\(\sqrt{5}-3\)=5-9=-4)। चरण 3: छिपे हुए संयुग्मी रूप को पहचानें।

Open Question Page
Ask Friends
Question 2/3 Expert Mathematics Real Numbers Irrational numbers Class 10 Level 13

यदि \(x=\sqrt{13}+2\), तो \(x^2-4x\) का मान क्या है?

If \(x=\sqrt{13}+2\), what is the value of \(x^2-4x\)?

Explanation opens after your attempt
Correct Answer

A. (9)

Step 1

Concept

Write (x-2-4x=x(x-4)).

Step 2

Why this answer is correct

With \(x=\sqrt{13}+2\), \(x-4=\sqrt{13}-2\), so the product is (13-4=9).

Step 3

Exam Tip

A conjugate form may be hidden in such expressions. चरण 1: (x-2-4x=x(x-4)) लिखें। चरण 2: \(x=\sqrt{13}+2\) होने पर \(x-4=\sqrt{13}-2\), इसलिए गुणन (13-4=9) है। चरण 3: ऐसे रूप में संयुग्मी छिपा हो सकता है।

Open Question Page
Ask Friends
Question 3/3 Expert Mathematics Real Numbers Irrational numbers Class 10 Level 13

यदि \(x=\sqrt{5}+\sqrt{3}\), तो \(x-\frac{2}{x}\) का मान क्या है?

If \(x=\sqrt{5}+\sqrt{3}\), what is the value of \(x-\frac{2}{x}\)?

Explanation opens after your attempt
Correct Answer

A. \(2\sqrt{3}\)

Step 1

Concept

\(\frac{1}{\sqrt{5}+\sqrt{3}}=\frac{\sqrt{5}-\sqrt{3}}{2}\).

Step 2

Why this answer is correct

Therefore \(\frac{2}{x}=\sqrt{5}-\sqrt{3}\).

Step 3

Exam Tip

(x-\frac{2}{x}=\(\sqrt{5}+\sqrt{3}\)-\(\sqrt{5}-\sqrt{3}\)=2\sqrt{3}). चरण 1: \(\frac{1}{\sqrt{5}+\sqrt{3}}=\frac{\sqrt{5}-\sqrt{3}}{2}\) होता है। चरण 2: इसलिए \(\frac{2}{x}=\sqrt{5}-\sqrt{3}\)। चरण 3: (x-\frac{2}{x}=\(\sqrt{5}+\sqrt{3}\)-\(\sqrt{5}-\sqrt{3}\)=2\sqrt{3})।

Open Question Page
Ask Friends

algebraic surds Revision Links

All MCQ Tags

Browse concept directory

All Subjects

Subject-wise practice

Search algebraic surds

More keyword results