यदि \(x=\sqrt{5}+\sqrt{3}\), तो \(x-\frac{2}{x}\) का मान क्या है?
If \(x=\sqrt{5}+\sqrt{3}\), what is the value of \(x-\frac{2}{x}\)?
Explanation opens after your attempt
A. \(2\sqrt{3}\)
Concept
\(\frac{1}{\sqrt{5}+\sqrt{3}}=\frac{\sqrt{5}-\sqrt{3}}{2}\).
Why this answer is correct
Therefore \(\frac{2}{x}=\sqrt{5}-\sqrt{3}\).
Exam Tip
(x-\frac{2}{x}=\(\sqrt{5}+\sqrt{3}\)-\(\sqrt{5}-\sqrt{3}\)=2\sqrt{3}). चरण 1: \(\frac{1}{\sqrt{5}+\sqrt{3}}=\frac{\sqrt{5}-\sqrt{3}}{2}\) होता है। चरण 2: इसलिए \(\frac{2}{x}=\sqrt{5}-\sqrt{3}\)। चरण 3: (x-\frac{2}{x}=\(\sqrt{5}+\sqrt{3}\)-\(\sqrt{5}-\sqrt{3}\)=2\sqrt{3})।
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