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3 results found for "fraction_roots" in Class 10.

Question Medium Mathematics Quadratic Equations Roots of a Quadratic Equation Class 10 Level 33

समीकरण \(10x^2-17x+3=0\) के मूल कौन से हैं?

What are the roots of \(10x^2-17x+3=0\)?

Explanation opens after your attempt
Correct Answer

A. \(\frac{3}{2}\) और \(\frac{1}{5}\)\(\frac{3}{2}\) and \(\frac{1}{5}\)

Step 1

Concept

(10x-2-17x+3=(2x-3)(5x-1)). Therefore the roots are \(\frac{3}{2}\) and \(\frac{1}{5}\).

Step 2

Why this answer is correct

The correct answer is A. \(\frac{3}{2}\) और \(\frac{1}{5}\) / \(\frac{3}{2}\) and \(\frac{1}{5}\). (10x-2-17x+3=(2x-3)(5x-1)). Therefore the roots are \(\frac{3}{2}\) and \(\frac{1}{5}\).

Step 3

Exam Tip

(10x-2-17x+3=(2x-3)(5x-1)) है। इसलिए मूल \(\frac{3}{2}\) और \(\frac{1}{5}\) हैं।

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Question Medium Mathematics Quadratic Equations Roots of a Quadratic Equation Class 10 Level 32

समीकरण \(8x^2-10x+3=0\) के मूल कौन से हैं?

What are the roots of \(8x^2-10x+3=0\)?

Explanation opens after your attempt
Correct Answer

A. \(\frac{1}{2}\) और \(\frac{3}{4}\)\(\frac{1}{2}\) and \(\frac{3}{4}\)

Step 1

Concept

(8x-2-10x+3=(2x-1)(4x-3)). Therefore the roots are \(\frac{1}{2}\) and \(\frac{3}{4}\).

Step 2

Why this answer is correct

The correct answer is A. \(\frac{1}{2}\) और \(\frac{3}{4}\) / \(\frac{1}{2}\) and \(\frac{3}{4}\). (8x-2-10x+3=(2x-1)(4x-3)). Therefore the roots are \(\frac{1}{2}\) and \(\frac{3}{4}\).

Step 3

Exam Tip

(8x-2-10x+3=(2x-1)(4x-3)) है। इसलिए मूल \(\frac{1}{2}\) और \(\frac{3}{4}\) हैं।

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Question Medium Mathematics Quadratic Equations Roots of a Quadratic Equation Class 10 Level 31

समीकरण \(6x^2-7x+2=0\) के मूल कौन से हैं?

What are the roots of \(6x^2-7x+2=0\)?

Explanation opens after your attempt
Correct Answer

A. \(\frac{1}{2}\) और \(\frac{2}{3}\)\(\frac{1}{2}\) and \(\frac{2}{3}\)

Step 1

Concept

(6x-2-7x+2=(3x-2)(2x-1)). Therefore the roots are \(\frac{2}{3}\) and \(\frac{1}{2}\).

Step 2

Why this answer is correct

The correct answer is A. \(\frac{1}{2}\) और \(\frac{2}{3}\) / \(\frac{1}{2}\) and \(\frac{2}{3}\). (6x-2-7x+2=(3x-2)(2x-1)). Therefore the roots are \(\frac{2}{3}\) and \(\frac{1}{2}\).

Step 3

Exam Tip

(6x-2-7x+2=(3x-2)(2x-1)) है। इसलिए मूल \(\frac{2}{3}\) और \(\frac{1}{2}\) हैं।

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