Search: fraction roots

Question Medium Mathematics Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 36

\(11x^2+12x+1=0\) के मूल क्या होंगे?

What will be the roots of \(11x^2+12x+1=0\)?

Explanation opens after your attempt

Correct Answer

A. \(x=-\frac{1}{11},-1\)

Step 1

Concept

((11x+1)(x+1)=0), so \(x=-\frac{1}{11}\) and (-1). In exams, ((11x+1)=0) gives \(-\frac{1}{11}\).

Step 2

Why this answer is correct

The correct answer is A. \(x=-\frac{1}{11},-1\). ((11x+1)(x+1)=0), so \(x=-\frac{1}{11}\) and (-1). In exams, ((11x+1)=0) gives \(-\frac{1}{11}\).

Step 3

Exam Tip

((11x+1)(x+1)=0), इसलिए \(x=-\frac{1}{11}\) और (-1) हैं। परीक्षा में ((11x+1)=0) से \(-\frac{1}{11}\) मिलता है।

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Question Medium Mathematics Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 36

\(5x^2+16x+3=0\) को हल करने पर मूल क्या होंगे?

What will be the roots after solving \(5x^2+16x+3=0\)?

Explanation opens after your attempt

Correct Answer

A. \(x=-3,-\frac{1}{5}\)

Step 1

Concept

(5x^-2+16x+3=(5x+1)(x+3)), so the roots are \(-\frac{1}{5}\) and (-3). In exams, positive factors give negative roots.

Step 2

Why this answer is correct

The correct answer is A. \(x=-3,-\frac{1}{5}\). (5x^-2+16x+3=(5x+1)(x+3)), so the roots are \(-\frac{1}{5}\) and (-3). In exams, positive factors give negative roots.

Step 3

Exam Tip

(5x^-2+16x+3=(5x+1)(x+3)), इसलिए मूल \(-\frac{1}{5}\) और (-3) हैं। परीक्षा में धनात्मक गुणनखंडों से ऋणात्मक मूल मिलते हैं।

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Question Medium Mathematics Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 36

\(12x^2+17x+5=0\) को गुणनखंड विधि से हल करने पर मूल क्या होंगे?

What roots are obtained by solving \(12x^2+17x+5=0\) by factorisation?

Explanation opens after your attempt

Correct Answer

A. \(x=-1,-\frac{5}{12}\)

Step 1

Concept

(12x^-2+17x+5=(12x+5)(x+1)), so the roots are \(-\frac{5}{12}\) and (-1). In exams, positive factors give negative roots.

Step 2

Why this answer is correct

The correct answer is A. \(x=-1,-\frac{5}{12}\). (12x^-2+17x+5=(12x+5)(x+1)), so the roots are \(-\frac{5}{12}\) and (-1). In exams, positive factors give negative roots.

Step 3

Exam Tip

(12x^-2+17x+5=(12x+5)(x+1)), इसलिए मूल \(-\frac{5}{12}\) और (-1) हैं। परीक्षा में धनात्मक गुणनखंडों से ऋणात्मक मूल मिलते हैं।

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Question Medium Mathematics Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 36

गुणनखंड विधि से \(7x^2-9x+2=0\) के मूल क्या होंगे?

Using factorisation method, what will be the roots of \(7x^2-9x+2=0\)?

Explanation opens after your attempt

Correct Answer

A. \(x=1,\frac{2}{7}\)

Step 1

Concept

(7x^-2-9x+2=(7x-2)(x-1)), so the roots are (1) and \(\frac{2}{7}\). In exams, solve each linear factor separately.

Step 2

Why this answer is correct

The correct answer is A. \(x=1,\frac{2}{7}\). (7x^-2-9x+2=(7x-2)(x-1)), so the roots are (1) and \(\frac{2}{7}\). In exams, solve each linear factor separately.

Step 3

Exam Tip

(7x^-2-9x+2=(7x-2)(x-1)), इसलिए मूल (1) और \(\frac{2}{7}\) हैं। परीक्षा में हर रैखिक गुणनखंड को अलग हल करें।

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Question Medium Mathematics Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 35

\(7x^2+8x+1=0\) के मूल क्या होंगे?

What will be the roots of \(7x^2+8x+1=0\)?

Explanation opens after your attempt

Correct Answer

A. \(x=-\frac{1}{7},-1\)

Step 1

Concept

((7x+1)(x+1)=0), so \(x=-\frac{1}{7}\) and (-1). In exams, ((7x+1)=0) gives \(-\frac{1}{7}\).

Step 2

Why this answer is correct

The correct answer is A. \(x=-\frac{1}{7},-1\). ((7x+1)(x+1)=0), so \(x=-\frac{1}{7}\) and (-1). In exams, ((7x+1)=0) gives \(-\frac{1}{7}\).

Step 3

Exam Tip

((7x+1)(x+1)=0), इसलिए \(x=-\frac{1}{7}\) और (-1) हैं। परीक्षा में ((7x+1)=0) से \(-\frac{1}{7}\) मिलता है।

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Question Medium Mathematics Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 35

\(3x^2+11x+10=0\) को हल करने पर मूल क्या होंगे?

What will be the roots after solving \(3x^2+11x+10=0\)?

Explanation opens after your attempt

Correct Answer

A. \(x=-2,-\frac{5}{3}\)

Step 1

Concept

(3x^-2+11x+10=(3x+5)(x+2)), so the roots are \(-\frac{5}{3}\) and (-2). In exams, positive factors give negative roots.

Step 2

Why this answer is correct

The correct answer is A. \(x=-2,-\frac{5}{3}\). (3x^-2+11x+10=(3x+5)(x+2)), so the roots are \(-\frac{5}{3}\) and (-2). In exams, positive factors give negative roots.

Step 3

Exam Tip

(3x^-2+11x+10=(3x+5)(x+2)), इसलिए मूल \(-\frac{5}{3}\) और (-2) हैं। परीक्षा में धनात्मक गुणनखंडों से ऋणात्मक मूल मिलते हैं।

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Question Medium Mathematics Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 35

\(3x^2+8x+4=0\) को गुणनखंड विधि से हल करने पर मूल क्या होंगे?

What roots are obtained by solving \(3x^2+8x+4=0\) by factorisation?

Explanation opens after your attempt

Correct Answer

A. \(x=-2,-\frac{2}{3}\)

Step 1

Concept

(3x^-2+8x+4=(3x+2)(x+2)), so the roots are \(-\frac{2}{3}\) and (-2). In exams, positive factors give negative roots.

Step 2

Why this answer is correct

The correct answer is A. \(x=-2,-\frac{2}{3}\). (3x^-2+8x+4=(3x+2)(x+2)), so the roots are \(-\frac{2}{3}\) and (-2). In exams, positive factors give negative roots.

Step 3

Exam Tip

(3x^-2+8x+4=(3x+2)(x+2)), इसलिए मूल \(-\frac{2}{3}\) और (-2) हैं। परीक्षा में धनात्मक गुणनखंडों से ऋणात्मक मूल मिलते हैं।

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Question Medium Mathematics Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 35

गुणनखंड विधि से \(4x^2-12x+5=0\) के मूल क्या होंगे?

Using factorisation method, what will be the roots of \(4x^2-12x+5=0\)?

Explanation opens after your attempt

Correct Answer

A. \(x=\frac{1}{2},\frac{5}{2}\)

Step 1

Concept

(4x^-2-12x+5=(2x-1)(2x-5)), so the roots are \(\frac{1}{2}\) and \(\frac{5}{2}\). In exams, solve each linear factor separately.

Step 2

Why this answer is correct

The correct answer is A. \(x=\frac{1}{2},\frac{5}{2}\). (4x^-2-12x+5=(2x-1)(2x-5)), so the roots are \(\frac{1}{2}\) and \(\frac{5}{2}\). In exams, solve each linear factor separately.

Step 3

Exam Tip

(4x^-2-12x+5=(2x-1)(2x-5)), इसलिए मूल \(\frac{1}{2}\) और \(\frac{5}{2}\) हैं। परीक्षा में हर रैखिक गुणनखंड को अलग हल करें।

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Question Medium Mathematics Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 34

\(5x^2+6x+1=0\) के मूल क्या होंगे?

What will be the roots of \(5x^2+6x+1=0\)?

Explanation opens after your attempt

Correct Answer

A. \(x=-\frac{1}{5},-1\)

Step 1

Concept

((5x+1)(x+1)=0), so \(x=-\frac{1}{5}\) and (-1). In exams, ((5x+1)=0) gives \(-\frac{1}{5}\).

Step 2

Why this answer is correct

The correct answer is A. \(x=-\frac{1}{5},-1\). ((5x+1)(x+1)=0), so \(x=-\frac{1}{5}\) and (-1). In exams, ((5x+1)=0) gives \(-\frac{1}{5}\).

Step 3

Exam Tip

((5x+1)(x+1)=0), इसलिए \(x=-\frac{1}{5}\) और (-1) हैं। परीक्षा में ((5x+1)=0) से \(-\frac{1}{5}\) मिलता है।

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Question Medium Mathematics Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 34

\(2x^2+7x+6=0\) को हल करने पर मूल क्या होंगे?

What will be the roots after solving \(2x^2+7x+6=0\)?

Explanation opens after your attempt

Correct Answer

A. \(x=-\frac{3}{2},-2\)

Step 1

Concept

(2x^-2+7x+6=(2x+3)(x+2)), so \(x=-\frac{3}{2}\) and (-2). In exams, positive factors give negative roots.

Step 2

Why this answer is correct

The correct answer is A. \(x=-\frac{3}{2},-2\). (2x^-2+7x+6=(2x+3)(x+2)), so \(x=-\frac{3}{2}\) and (-2). In exams, positive factors give negative roots.

Step 3

Exam Tip

(2x^-2+7x+6=(2x+3)(x+2)), इसलिए \(x=-\frac{3}{2}\) और (-2) हैं। परीक्षा में धनात्मक गुणनखंडों से ऋणात्मक मूल मिलते हैं।

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Question Medium Mathematics Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 34

\(3x^2+5x-2=0\) को गुणनखंड विधि से हल करने पर मूल क्या होंगे?

What roots are obtained by solving \(3x^2+5x-2=0\) by factorisation?

Explanation opens after your attempt

Correct Answer

A. \(x=\frac{1}{3},-2\)

Step 1

Concept

(3x^-2+5x-2=(3x-1)(x+2)), so the roots are \(\frac{1}{3}\) and (-2). In exams, solve (3x-1=0) carefully.

Step 2

Why this answer is correct

The correct answer is A. \(x=\frac{1}{3},-2\). (3x^-2+5x-2=(3x-1)(x+2)), so the roots are \(\frac{1}{3}\) and (-2). In exams, solve (3x-1=0) carefully.

Step 3

Exam Tip

(3x^-2+5x-2=(3x-1)(x+2)), इसलिए मूल \(\frac{1}{3}\) और (-2) हैं। परीक्षा में (3x-1=0) को सावधानी से हल करें।

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Question Medium Mathematics Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 34

\(3x^2-2x-1=0\) के मूल कौनसे हैं?

Which are the roots of \(3x^2-2x-1=0\)?

Explanation opens after your attempt

Correct Answer

A. \(x=1,-\frac{1}{3}\)

Step 1

Concept

(3x^-2-2x-1=(3x+1)(x-1)), so the roots are (1) and \(-\frac{1}{3}\). In exams, form mixed-sign factors carefully.

Step 2

Why this answer is correct

The correct answer is A. \(x=1,-\frac{1}{3}\). (3x^-2-2x-1=(3x+1)(x-1)), so the roots are (1) and \(-\frac{1}{3}\). In exams, form mixed-sign factors carefully.

Step 3

Exam Tip

(3x^-2-2x-1=(3x+1)(x-1)), इसलिए मूल (1) और \(-\frac{1}{3}\) हैं। परीक्षा में मिश्रित चिन्ह वाले गुणनखंड सावधानी से बनाएं।

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Question Easy Mathematics Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 36

\(3x^2-11x+6=0\) के मूल क्या हैं?

What are the roots of \(3x^2-11x+6=0\)?

Explanation opens after your attempt

Correct Answer

A. \(x=3,\frac{2}{3}\)

Step 1

Concept

((3x-2)(x-3)=0), so \(x=\frac{2}{3}\) and (x=3). In exams, solve (3x-2=0) carefully.

Step 2

Why this answer is correct

The correct answer is A. \(x=3,\frac{2}{3}\). ((3x-2)(x-3)=0), so \(x=\frac{2}{3}\) and (x=3). In exams, solve (3x-2=0) carefully.

Step 3

Exam Tip

((3x-2)(x-3)=0), इसलिए \(x=\frac{2}{3}\) और (x=3) हैं। परीक्षा में (3x-2=0) को ध्यान से हल करें।

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Question Easy Mathematics Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 36

\(16x^2-25=0\) के मूल क्या हैं?

What are the roots of \(16x^2-25=0\)?

Explanation opens after your attempt

Correct Answer

A. \(x=\frac{5}{4},-\frac{5}{4}\)

Step 1

Concept

((4x-5)(4x+5)=0), so \(x=\frac{5}{4}\) or \(x=-\frac{5}{4}\). In exams, solve linear factors carefully.

Step 2

Why this answer is correct

The correct answer is A. \(x=\frac{5}{4},-\frac{5}{4}\). ((4x-5)(4x+5)=0), so \(x=\frac{5}{4}\) or \(x=-\frac{5}{4}\). In exams, solve linear factors carefully.

Step 3

Exam Tip

((4x-5)(4x+5)=0), इसलिए \(x=\frac{5}{4}\) या \(x=-\frac{5}{4}\) है। परीक्षा में रैखिक गुणनखंड सावधानी से हल करें।

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Question Easy Mathematics Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 35

\(2x^2-7x+5=0\) के मूल क्या हैं?

What are the roots of \(2x^2-7x+5=0\)?

Explanation opens after your attempt

Correct Answer

A. \(x=1,\frac{5}{2}\)

Step 1

Concept

((2x-5)(x-1)=0), so \(x=\frac{5}{2}\) and (x=1). In exams, solve (2x-5=0) carefully.

Step 2

Why this answer is correct

The correct answer is A. \(x=1,\frac{5}{2}\). ((2x-5)(x-1)=0), so \(x=\frac{5}{2}\) and (x=1). In exams, solve (2x-5=0) carefully.

Step 3

Exam Tip

((2x-5)(x-1)=0), इसलिए \(x=\frac{5}{2}\) और (x=1) हैं। परीक्षा में (2x-5=0) को ध्यान से हल करें।

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Question Easy Mathematics Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 35

\(9x^2-16=0\) के मूल क्या हैं?

What are the roots of \(9x^2-16=0\)?

Explanation opens after your attempt

Correct Answer

A. \(x=\frac{4}{3},-\frac{4}{3}\)

Step 1

Concept

((3x-4)(3x+4)=0), so \(x=\frac{4}{3}\) or \(x=-\frac{4}{3}\). In exams, solve linear factors carefully.

Step 2

Why this answer is correct

The correct answer is A. \(x=\frac{4}{3},-\frac{4}{3}\). ((3x-4)(3x+4)=0), so \(x=\frac{4}{3}\) or \(x=-\frac{4}{3}\). In exams, solve linear factors carefully.

Step 3

Exam Tip

((3x-4)(3x+4)=0), इसलिए \(x=\frac{4}{3}\) या \(x=-\frac{4}{3}\) है। परीक्षा में रैखिक गुणनखंड सावधानी से हल करें।

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Question Easy Mathematics Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 34

\(4x^2-1=0\) के मूल क्या हैं?

What are the roots of \(4x^2-1=0\)?

Explanation opens after your attempt

Correct Answer

A. \(x=\frac{1}{2},-\frac{1}{2}\)

Step 1

Concept

((2x-1)(2x+1)=0), so \(x=\frac{1}{2}\) or \(x=-\frac{1}{2}\). In exams, solve each linear factor carefully.

Step 2

Why this answer is correct

The correct answer is A. \(x=\frac{1}{2},-\frac{1}{2}\). ((2x-1)(2x+1)=0), so \(x=\frac{1}{2}\) or \(x=-\frac{1}{2}\). In exams, solve each linear factor carefully.

Step 3

Exam Tip

((2x-1)(2x+1)=0), इसलिए \(x=\frac{1}{2}\) या \(x=-\frac{1}{2}\) है। परीक्षा में रैखिक गुणनखंड को सावधानी से हल करें।

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Question Medium Mathematics Quadratic Equations Roots of a Quadratic Equation Class 10 Level 33

समीकरण \(10x^2-17x+3=0\) के मूल कौन से हैं?

What are the roots of \(10x^2-17x+3=0\)?

Explanation opens after your attempt

Correct Answer

A. \(\frac{3}{2}\) और \(\frac{1}{5}\)\(\frac{3}{2}\) and \(\frac{1}{5}\)

Step 1

Concept

(10x^-2-17x+3=(2x-3)(5x-1)). Therefore the roots are \(\frac{3}{2}\) and \(\frac{1}{5}\).

Step 2

Why this answer is correct

The correct answer is A. \(\frac{3}{2}\) और \(\frac{1}{5}\) / \(\frac{3}{2}\) and \(\frac{1}{5}\). (10x^-2-17x+3=(2x-3)(5x-1)). Therefore the roots are \(\frac{3}{2}\) and \(\frac{1}{5}\).

Step 3

Exam Tip

(10x^-2-17x+3=(2x-3)(5x-1)) है। इसलिए मूल \(\frac{3}{2}\) और \(\frac{1}{5}\) हैं।

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Question Medium Mathematics Quadratic Equations Roots of a Quadratic Equation Class 10 Level 32

समीकरण \(8x^2-10x+3=0\) के मूल कौन से हैं?

What are the roots of \(8x^2-10x+3=0\)?

Explanation opens after your attempt

Correct Answer

A. \(\frac{1}{2}\) और \(\frac{3}{4}\)\(\frac{1}{2}\) and \(\frac{3}{4}\)

Step 1

Concept

(8x^-2-10x+3=(2x-1)(4x-3)). Therefore the roots are \(\frac{1}{2}\) and \(\frac{3}{4}\).

Step 2

Why this answer is correct

The correct answer is A. \(\frac{1}{2}\) और \(\frac{3}{4}\) / \(\frac{1}{2}\) and \(\frac{3}{4}\). (8x^-2-10x+3=(2x-1)(4x-3)). Therefore the roots are \(\frac{1}{2}\) and \(\frac{3}{4}\).

Step 3

Exam Tip

(8x^-2-10x+3=(2x-1)(4x-3)) है। इसलिए मूल \(\frac{1}{2}\) और \(\frac{3}{4}\) हैं।

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Question Medium Mathematics Quadratic Equations Roots of a Quadratic Equation Class 10 Level 31

समीकरण \(6x^2-7x+2=0\) के मूल कौन से हैं?

What are the roots of \(6x^2-7x+2=0\)?

Explanation opens after your attempt

Correct Answer

A. \(\frac{1}{2}\) और \(\frac{2}{3}\)\(\frac{1}{2}\) and \(\frac{2}{3}\)

Step 1

Concept

(6x^-2-7x+2=(3x-2)(2x-1)). Therefore the roots are \(\frac{2}{3}\) and \(\frac{1}{2}\).

Step 2

Why this answer is correct

The correct answer is A. \(\frac{1}{2}\) और \(\frac{2}{3}\) / \(\frac{1}{2}\) and \(\frac{2}{3}\). (6x^-2-7x+2=(3x-2)(2x-1)). Therefore the roots are \(\frac{2}{3}\) and \(\frac{1}{2}\).

Step 3

Exam Tip

(6x^-2-7x+2=(3x-2)(2x-1)) है। इसलिए मूल \(\frac{2}{3}\) और \(\frac{1}{2}\) हैं।

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Search Class 10 Questions

\(11x^2+12x+1=0\) के मूल क्या होंगे?

Concept

Why this answer is correct

Exam Tip

\(5x^2+16x+3=0\) को हल करने पर मूल क्या होंगे?

Concept

Why this answer is correct

Exam Tip

\(12x^2+17x+5=0\) को गुणनखंड विधि से हल करने पर मूल क्या होंगे?

Concept

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Exam Tip

गुणनखंड विधि से \(7x^2-9x+2=0\) के मूल क्या होंगे?

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Exam Tip

\(7x^2+8x+1=0\) के मूल क्या होंगे?

Concept

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Exam Tip

\(3x^2+11x+10=0\) को हल करने पर मूल क्या होंगे?

Concept

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Exam Tip

\(3x^2+8x+4=0\) को गुणनखंड विधि से हल करने पर मूल क्या होंगे?

Concept

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Exam Tip

गुणनखंड विधि से \(4x^2-12x+5=0\) के मूल क्या होंगे?

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Exam Tip

\(5x^2+6x+1=0\) के मूल क्या होंगे?

Concept

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Exam Tip

\(2x^2+7x+6=0\) को हल करने पर मूल क्या होंगे?

Concept

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Exam Tip

\(3x^2+5x-2=0\) को गुणनखंड विधि से हल करने पर मूल क्या होंगे?

Concept

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Exam Tip

\(3x^2-2x-1=0\) के मूल कौनसे हैं?

Concept

Why this answer is correct

Exam Tip

\(3x^2-11x+6=0\) के मूल क्या हैं?

Concept

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Exam Tip

\(16x^2-25=0\) के मूल क्या हैं?

Concept

Why this answer is correct

Exam Tip

\(2x^2-7x+5=0\) के मूल क्या हैं?

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\(9x^2-16=0\) के मूल क्या हैं?

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Exam Tip

\(4x^2-1=0\) के मूल क्या हैं?

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Exam Tip

समीकरण \(10x^2-17x+3=0\) के मूल कौन से हैं?

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Exam Tip

समीकरण \(8x^2-10x+3=0\) के मूल कौन से हैं?

Concept

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Exam Tip

समीकरण \(6x^2-7x+2=0\) के मूल कौन से हैं?

Concept

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