Hard Mathematics Chapter 1: Real Numbers Class 10 Level 17

\(\sqrt{5}\) की सिद्धि में (p=5k) और (q=5r) मिलने पर कौन सी आरंभिक शर्त टूटती है?

In the proof of \(\sqrt{5}\), if (p=5k) and (q=5r) are obtained, which initial condition breaks?

Explanation opens after your attempt
Correct Answer

A. (p) और (q) सहअभाज्य हैं(p) and (q) are coprime

Step 1

Concept

(p=5k) and (q=5r) show factor (5) in both (p) and (q).

Step 2

Why this answer is correct

So they cannot be coprime.

Step 3

Exam Tip

This breaks the initial lowest-form condition. चरण 1: (p=5k) और (q=5r) से (p) और (q) दोनों में (5) गुणनखंड है। चरण 2: इसलिए वे सहअभाज्य नहीं हो सकते। चरण 3: यह आरंभिक सरलतम रूप की शर्त को तोड़ता है।

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The correct answer is A. (p) और (q) सहअभाज्य हैं / (p) and (q) are coprime.

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