Hard Mathematics Chapter 1: Real Numbers Class 10 Level 16

\(\sqrt{2}\) की सिद्धि में (p=2r) रखने पर \(p^2=2q^2\) से कौन सा सही सरलीकरण प्राप्त होता है?

In the proof of \(\sqrt{2}\), after putting (p=2r), which correct simplification is obtained from \(p^2=2q^2\)?

Explanation opens after your attempt
Correct Answer

A. \(q^2=2r^2\)

Step 1

Concept

If (p=2r), then \(p^2=4r^2\).

Step 2

Why this answer is correct

From \(4r^2=2q^2\), dividing both sides by (2) gives \(q^2=2r^2\).

Step 3

Exam Tip

This proves \(q^2\), and then (q), is even. चरण 1: (p=2r) रखने पर \(p^2=4r^2\) होगा। चरण 2: \(4r^2=2q^2\) से दोनों ओर (2) से भाग करने पर \(q^2=2r^2\) मिलता है। चरण 3: इससे \(q^2\) सम और फिर (q) सम सिद्ध होता है।

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What is the correct answer to this Mathematics MCQ?

The correct answer is A. \(q^2=2r^2\).

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