यदि \(2^8\times3^3\times5^2\) और \(2^5\times3^7\times5\) का महत्तम समापवर्तक (H) और लघुत्तम समापवर्त्य (L) है, तो \(\frac{L}{H}\) क्या होगा?
If (H) is the HCF and (L) is the LCM of \(2^8\times3^3\times5^2\) and \(2^5\times3^7\times5\), what is \(\frac{L}{H}\)?
Explanation opens after your attempt
Correct Answer
A. \(2^3\times3^4\times5\)
Concept
\(H=2^5\times3^3\times5\) and \(L=2^8\times3^7\times5^2\).
Why this answer is correct
\(\frac{L}{H}=2^{8-5}\times3^{7-3}\times5^{2-1}=2^3\times3^4\times5\).
Exam Tip
In division, subtract powers of the same base. चरण 1: \(H=2^5\times3^3\times5\) और \(L=2^8\times3^7\times5^2\) होगा। चरण 2: \(\frac{L}{H}=2^{8-5}\times3^{7-3}\times5^{2-1}=2^3\times3^4\times5\) है। चरण 3: भाग में समान आधारों की घातें घटाएँ।
Login to save your score, XP, coins and progress.