Medium Mathematics Relations and Functions Class 12 Level 24

यदि \(f:\mathbb{R}\to\mathbb{R}\) और (f(x)=\frac{x+1}{2}) है, तो (f) के लिए सही निष्कर्ष चुनिए।

If \(f:\mathbb{R}\to\mathbb{R}\) and (f(x)=\frac{x+1}{2}), choose the correct conclusion for (f).

Explanation opens after your attempt
Correct Answer

A. एकैकी हैOne-one

Step 1

Concept

Assume (f(a)=f(b)).

Step 2

Why this answer is correct

From \(\frac{a+1}{2}=\frac{b+1}{2}\), we get (a+1=b+1), so (a=b).

Step 3

Exam Tip

Even in fractional form, a linear function with non-zero coefficient is one-one. चरण 1: मान लें (f(a)=f(b))। चरण 2: \(\frac{a+1}{2}=\frac{b+1}{2}\) से (a+1=b+1), इसलिए (a=b)। चरण 3: भिन्न रूप में भी गैर-शून्य गुणांक वाला रैखिक फलन एकैकी होता है।

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Mathematics Answer, Explanation and Revision Hints

यदि \(f:\mathbb{R}\to\mathbb{R}\) और (f(x)=\frac{x+1}{2}) है, तो (f) के लिए सही निष्कर्ष चुनिए। / If \(f:\mathbb{R}\to\mathbb{R}\) and (f(x)=\frac{x+1}{2}), choose the correct conclusion for (f).

Correct Answer: A. एकैकी है / One-one. Explanation: चरण 1: मान लें (f(a)=f(b))। चरण 2: \(\frac{a+1}{2}=\frac{b+1}{2}\) से (a+1=b+1), इसलिए (a=b)। चरण 3: भिन्न रूप में भी गैर-शून्य गुणांक वाला रैखिक फलन एकैकी होता है। / Step 1: Assume (f(a)=f(b)). Step 2: From \(\frac{a+1}{2}=\frac{b+1}{2}\), we get (a+1=b+1), so (a=b). Step 3: Even in fractional form, a linear function with non-zero coefficient is one-one.

Which concept should I revise for this Mathematics MCQ?

Assume (f(a)=f(b)).

What exam hint can help solve this Mathematics question?

Even in fractional form, a linear function with non-zero coefficient is one-one. चरण 1: मान लें (f(a)=f(b))। चरण 2: \(\frac{a+1}{2}=\frac{b+1}{2}\) से (a+1=b+1), इसलिए (a=b)। चरण 3: भिन्न रूप में भी गैर-शून्य गुणांक वाला रैखिक फलन एकैकी होता है।

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