यदि \(a=3+\sqrt{5}\), तो \(a^2-6a\) का मान क्या है?
If \(a=3+\sqrt{5}\), what is the value of \(a^2-6a\)?
Explanation opens after your attempt
A. (-4)
Concept
(a-2-6a=a(a-6)).
Why this answer is correct
\(a-6=\sqrt{5}-3\), so (a(a-6)=\(3+\sqrt{5}\)\(\sqrt{5}-3\)=5-9=-4).
Exam Tip
Recognize the hidden conjugate form. चरण 1: (a-2-6a=a(a-6)) है। चरण 2: \(a-6=\sqrt{5}-3\), इसलिए (a(a-6)=\(3+\sqrt{5}\)\(\sqrt{5}-3\)=5-9=-4)। चरण 3: छिपे हुए संयुग्मी रूप को पहचानें।
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