\(\frac{484}{2^4\cdot 5^3\cdot 11^2}\) को सरलतम रूप में लिखने के बाद दशमलव प्रसार कितने स्थानों पर समाप्त होगा?
After reducing \(\frac{484}{2^4\cdot 5^3\cdot 11^2}\) to lowest form, after how many decimal places will its decimal expansion terminate?
Explanation opens after your attempt
B. (3) स्थान(3) places
Concept
Since \(484=2^2\cdot 11^2\), the reduced denominator is \(2^2\cdot 5^3\). The larger exponent is (3), so reduce first and then count decimal places.
Why this answer is correct
The correct answer is B. (3) स्थान / (3) places. Since \(484=2^2\cdot 11^2\), the reduced denominator is \(2^2\cdot 5^3\). The larger exponent is (3), so reduce first and then count decimal places.
Exam Tip
\(484=2^2\cdot 11^2\) कटने पर हर \(2^2\cdot 5^3\) बचता है। बड़ी घात (3) है इसलिए पहले सरल करें फिर दशमलव स्थान गिनें।
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