वर्गमूल सर्पिल में \(\sqrt{3}\) को \(\sqrt{2}\) से बनाते समय कौन-सी भुजाएँ समकोण बनाती हैं?
While making \(\sqrt{3}\) from \(\sqrt{2}\) in a square root spiral, which sides form the right angle?
Explanation opens after your attempt
Correct Answer
A. \(\sqrt{2}\) और (1)\(\sqrt{2}\) and (1)
Concept
The previous hypotenuse \(\sqrt{2}\) becomes one side and a (1) unit perpendicular is added. The new hypotenuse is \(\sqrt{3}\).
Why this answer is correct
The correct answer is A. \(\sqrt{2}\) और (1) / \(\sqrt{2}\) and (1). The previous hypotenuse \(\sqrt{2}\) becomes one side and a (1) unit perpendicular is added. The new hypotenuse is \(\sqrt{3}\).
Exam Tip
पिछला कर्ण \(\sqrt{2}\) नई भुजा बनता है और (1) इकाई लंब जोड़ी जाती है। नया कर्ण \(\sqrt{3}\) होता है।
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