वर्गमूल सर्पिल में \( \sqrt{2} \) से \( \sqrt{3} \) बनाते समय कौन-सा त्रिभुज बनता है?
Which triangle is formed while constructing \( \sqrt{3} \) from \( \sqrt{2} \) in the square root spiral?
Explanation opens after your attempt
Correct Answer
A. भुजाएँ \( \sqrt{2} \), (1), कर्ण \( \sqrt{3} \)Sides \( \sqrt{2} \), (1), hypotenuse \( \sqrt{3} \)
Concept
The old hypotenuse \( \sqrt{2} \) makes a right angle with the new side (1). The new hypotenuse is \( \sqrt{3} \).
Why this answer is correct
The correct answer is A. भुजाएँ \( \sqrt{2} \), (1), कर्ण \( \sqrt{3} \) / Sides \( \sqrt{2} \), (1), hypotenuse \( \sqrt{3} \). The old hypotenuse \( \sqrt{2} \) makes a right angle with the new side (1). The new hypotenuse is \( \sqrt{3} \).
Exam Tip
पुराना कर्ण \( \sqrt{2} \) नई भुजा (1) के साथ समकोण बनाता है। नया कर्ण \( \sqrt{3} \) होता है।
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