कौन सा क्रम \(a_n=2^n+1\) से बने पहले चार पद दिखाता है?

Which sequence shows the first four terms of \(a_n=2^n+1\)?

Author: Muft Shiksha Editorial Team Published:
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Correct Answer

B. (3,5,9,17)

Step 1

Concept

\(2^1+1=3\), \(2^2+1=5\), \(2^3+1=9\), and \(2^4+1=17\). Add (1) after evaluating the power.

Step 2

Why this answer is correct

The correct answer is B. (3,5,9,17). \(2^1+1=3\), \(2^2+1=5\), \(2^3+1=9\), and \(2^4+1=17\). Add (1) after evaluating the power.

Step 3

Exam Tip

\(2^1+1=3\), \(2^2+1=5\), \(2^3+1=9\), \(2^4+1=17\)। घात के बाद (1) जोड़ें।

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Mathematics Answer, Explanation and Revision Hints

कौन सा क्रम \(a_n=2^n+1\) से बने पहले चार पद दिखाता है? / Which sequence shows the first four terms of \(a_n=2^n+1\)?

Correct Answer: B. (3,5,9,17). Explanation: \(2^1+1=3\), \(2^2+1=5\), \(2^3+1=9\), \(2^4+1=17\)। घात के बाद (1) जोड़ें। / \(2^1+1=3\), \(2^2+1=5\), \(2^3+1=9\), and \(2^4+1=17\). Add (1) after evaluating the power.

Which concept should I revise for this Mathematics MCQ?

\(2^1+1=3\), \(2^2+1=5\), \(2^3+1=9\), and \(2^4+1=17\). Add (1) after evaluating the power.

What exam hint can help solve this Mathematics question?

\(2^1+1=3\), \(2^2+1=5\), \(2^3+1=9\), \(2^4+1=17\)। घात के बाद (1) जोड़ें।