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Which relation is correct between \(\sqrt{36}\) and \(\sqrt{64}\)?

Answer and explanation

Correct answer: \(\sqrt{36}<\sqrt{64}\)

\(\sqrt{36}=6\) and \(\sqrt{64}=8\), so \(6<8\), which gives \(\sqrt{36}<\sqrt{64}\). Therefore, option C is correct. Option A reverses the inequality, while option B incorrectly treats the two values as equal. Option D is also incorrect because 6 and 8 are both real and rational numbers. Exam tip: For perfect squares, calculate their square roots first and then compare the results.

Related tags

Real NumbersSquare RootsComparisonClass 9 MathematicsNumber SystemsMathematicsClass 9 Mcq

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