Which option is the fractional form of (0.\overline{6})?

Correct answer: \(\frac{2}{3}\)

Let \(x=0.\overline{6}\). Since 6 repeats indefinitely, \(10x=6.\overline{6}\). Subtracting the original equation gives \(10x-x=6.\overline{6}-0.\overline{6}\), so \(9x=6\) and \(x=\frac{6}{9}=\frac{2}{3}\). Therefore, option B is correct. Option C, \(\frac{3}{5}\), equals the terminating decimal \(0.6\), not the recurring decimal \(0.\overline{6}\). Exam tip: a one-digit recurring decimal \(0.\overline{a}\) can be written as \(\frac{a}{9}\) and then reduced.