किस विकल्प में वर्गमूल सर्पिल के पहले चार कर्णों का सही क्रम है?
Which option gives the correct order of the first four hypotenuse lengths in the square root spiral?
Explanation opens after your attempt
Correct Answer
C. \( \sqrt{2},\sqrt{3},\sqrt{4},\sqrt{5} \)
Concept
If hypotenuses are counted from the first right triangle, the sequence starts at \( \sqrt{2} \). The base \( \sqrt{1} \) is the initial radius.
Why this answer is correct
The correct answer is C. \( \sqrt{2},\sqrt{3},\sqrt{4},\sqrt{5} \). If hypotenuses are counted from the first right triangle, the sequence starts at \( \sqrt{2} \). The base \( \sqrt{1} \) is the initial radius.
Exam Tip
यदि कर्णों को पहले बने समकोण त्रिभुज से गिनें, तो क्रम \( \sqrt{2} \) से शुरू होता है। आधार \( \sqrt{1} \) प्रारंभिक त्रिज्या है।
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