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Which option gives the correct conclusion and reason for the proof of √3?

Answer and explanation

Correct answer: Irrational because the rational assumption makes both p and q divisible by 3

Assume √3 = p/q in lowest terms, with q ≠ 0. Squaring gives p² = 3q². Since 3 divides p², the prime-divisibility property implies that 3 divides p. Let p = 3k; substitution gives q² = 3k², so 3 divides q as well. This creates a common factor 3 in p and q, contradicting the lowest-terms assumption. Therefore the initial assumption that √3 is rational is false, and √3 is irrational. Option C merely repeats an intermediate equation and does not establish rationality. Options A and D confuse the contradiction with an unrelated conclusion. Hence option B gives both the correct conclusion and its reason.

Related tags

Number-SystemsSquare-Root-3Conclusion-And-ReasonProof Of Irrationality Of Square Root 2 And Square Root 3Number SystemsMathematicsClass 9 Mcq

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