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Which option contains only irrational numbers?

Answer and explanation

Correct answer: (\sqrt{6}), (\sqrt{10}), (\sqrt{15})

Irrational numbers have non-terminating, non-repeating decimal expansions. The square root of a perfect square is rational (for example \(\sqrt{4}=2\)), while the square root of a non-perfect square is irrational. In option A, \(\sqrt{6},\ \sqrt{10},\ \sqrt{15}\) are not square roots of perfect squares, so all three are irrational. The closest distractor B is wrong because \(\sqrt{4}=2\) is rational. Options C and D are also incorrect since \(\tfrac{1}{2}\) and \(0\) are rational. Exam tip: when checking square roots, first test if the radicand is a perfect square — if it is, the root is rational.

Related tags

Irrational-NumbersSquare-RootsNumber-ClassificationReal-NumbersReal NumbersNumber SystemsMathematicsClass 9 Mcq

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