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Which of the following expressions is a difference of two perfect squares and can be factorised using the identity \(A^2-B^2=(A-B)(A+B)\)?
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Answer and explanation
Correct answer: \(m^2-36n^2\)
\(m^2-36n^2=m^2-(6n)^2\), so it is a difference of perfect squares and becomes \((m-6n)(m+6n)\). Option A is a sum, while C is a perfect-square trinomial. Exam tip: check for squared terms with a minus sign between them.
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What is the correct answer to this question?
\(m^2-36n^2\)
Why is this the correct answer?
\(m^2-36n^2=m^2-(6n)^2\), so it is a difference of perfect squares and becomes \((m-6n)(m+6n)\). Option A is a sum, while C is a perfect-square trinomial. Exam tip: check for squared terms with a minus sign between them.
Which subject and chapter does this question cover?
This is a Class 9 Mathematics question. Chapter: Exploring Algebraic Identities. Topic: Factorisation.
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