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Which of the following expressions can be factorised as the product of two identical binomials?
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Answer and explanation
Correct answer: \(a^2+6ab+9b^2\)
In \(a^2+6ab+9b^2\), the first and last terms are \(a^2\) and \((3b)^2\). The middle term is \(2\times a\times3b=6ab\), so it equals \((a+3b)^2\). Exam tip: always verify the middle coefficient.
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What is the correct answer to this question?
\(a^2+6ab+9b^2\)
Why is this the correct answer?
In \(a^2+6ab+9b^2\), the first and last terms are \(a^2\) and \((3b)^2\). The middle term is \(2\times a\times3b=6ab\), so it equals \((a+3b)^2\). Exam tip: always verify the middle coefficient.
Which subject and chapter does this question cover?
This is a Class 9 Mathematics question. Chapter: Exploring Algebraic Identities. Topic: Factorisation.
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