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Which of the following is the simplest form of \(\sqrt{63}\)?

Answer and explanation

Correct answer: \(3\sqrt{7}\)

Since \(63=9\times7\) and \(9\) is a perfect square, \(\sqrt{63}=\sqrt{9\times7}=\sqrt{9}\times\sqrt{7}=3\sqrt{7}\). Option A results from incorrectly treating \(7\) as a perfect square. In exams, identify the greatest perfect-square factor of the number under the radical.

Related tags

Real NumbersSurd SimplificationPerfect SquaresNumber SystemsMathematicsClass 9 Mcq

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