\(\frac{\sqrt{31}+\sqrt{19}}{\sqrt{31}-\sqrt{19}}\) का सरल रूप कौन-सा है?

Which is the simplified form of \(\frac{\sqrt{31}+\sqrt{19}}{\sqrt{31}-\sqrt{19}}\)?

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

A. \(\frac{25+\sqrt{589}}{6}\)

Step 1

Concept

Multiplying by the conjugate gives numerator \(50+2\sqrt{589}\) and denominator (12). The simplified form is \(\frac{25+\sqrt{589}}{6}\).

Step 2

Why this answer is correct

The correct answer is A. \(\frac{25+\sqrt{589}}{6}\). Multiplying by the conjugate gives numerator \(50+2\sqrt{589}\) and denominator (12). The simplified form is \(\frac{25+\sqrt{589}}{6}\).

Step 3

Exam Tip

संयुग्मी से गुणा करने पर अंश \(50+2\sqrt{589}\) और हर (12) मिलता है। सरल रूप \(\frac{25+\sqrt{589}}{6}\) है।

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Mathematics Answer, Explanation and Revision Hints

\(\frac{\sqrt{31}+\sqrt{19}}{\sqrt{31}-\sqrt{19}}\) का सरल रूप कौन-सा है? / Which is the simplified form of \(\frac{\sqrt{31}+\sqrt{19}}{\sqrt{31}-\sqrt{19}}\)?

Correct Answer: A. \(\frac{25+\sqrt{589}}{6}\). Explanation: संयुग्मी से गुणा करने पर अंश \(50+2\sqrt{589}\) और हर (12) मिलता है। सरल रूप \(\frac{25+\sqrt{589}}{6}\) है। / Multiplying by the conjugate gives numerator \(50+2\sqrt{589}\) and denominator (12). The simplified form is \(\frac{25+\sqrt{589}}{6}\).

Which concept should I revise for this Mathematics MCQ?

Multiplying by the conjugate gives numerator \(50+2\sqrt{589}\) and denominator (12). The simplified form is \(\frac{25+\sqrt{589}}{6}\).

What exam hint can help solve this Mathematics question?

संयुग्मी से गुणा करने पर अंश \(50+2\sqrt{589}\) और हर (12) मिलता है। सरल रूप \(\frac{25+\sqrt{589}}{6}\) है।