\(\frac{\sqrt{3}-1}{\sqrt{3}+1}\) का सरल रूप कौन-सा है?

Which is the simplified form of \(\frac{\sqrt{3}-1}{\sqrt{3}+1}\)?

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

A. \(2-\sqrt{3}\)

Step 1

Concept

Multiplying by the conjugate gives (\frac{\(\sqrt{3}-1\)2}{2}=\frac{4-2\sqrt{3}}{2}=2-\sqrt{3}). Rationalise the denominator.

Step 2

Why this answer is correct

The correct answer is A. \(2-\sqrt{3}\). Multiplying by the conjugate gives (\frac{\(\sqrt{3}-1\)2}{2}=\frac{4-2\sqrt{3}}{2}=2-\sqrt{3}). Rationalise the denominator.

Step 3

Exam Tip

संयुग्मी से गुणा करने पर (\frac{\(\sqrt{3}-1\)2}{2}=\frac{4-2\sqrt{3}}{2}=2-\sqrt{3}) मिलता है। हर का परिमेयकरण करें।

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Mathematics Answer, Explanation and Revision Hints

\(\frac{\sqrt{3}-1}{\sqrt{3}+1}\) का सरल रूप कौन-सा है? / Which is the simplified form of \(\frac{\sqrt{3}-1}{\sqrt{3}+1}\)?

Correct Answer: A. \(2-\sqrt{3}\). Explanation: संयुग्मी से गुणा करने पर (\frac{\(\sqrt{3}-1\)2}{2}=\frac{4-2\sqrt{3}}{2}=2-\sqrt{3}) मिलता है। हर का परिमेयकरण करें। / Multiplying by the conjugate gives (\frac{\(\sqrt{3}-1\)2}{2}=\frac{4-2\sqrt{3}}{2}=2-\sqrt{3}). Rationalise the denominator.

Which concept should I revise for this Mathematics MCQ?

Multiplying by the conjugate gives (\frac{\(\sqrt{3}-1\)2}{2}=\frac{4-2\sqrt{3}}{2}=2-\sqrt{3}). Rationalise the denominator.

What exam hint can help solve this Mathematics question?

संयुग्मी से गुणा करने पर (\frac{\(\sqrt{3}-1\)2}{2}=\frac{4-2\sqrt{3}}{2}=2-\sqrt{3}) मिलता है। हर का परिमेयकरण करें।