\(\frac{\sqrt{13}+\sqrt{3}}{\sqrt{13}-\sqrt{3}}\) का सरल रूप कौन-सा है?
Which is the simplified form of \(\frac{\sqrt{13}+\sqrt{3}}{\sqrt{13}-\sqrt{3}}\)?
Explanation opens after your attempt
C. \(\frac{8+\sqrt{39}}{5}\)
Concept
Multiplying by the conjugate gives numerator \(16+2\sqrt{39}\) and denominator (10). So the answer is \(\frac{8+\sqrt{39}}{5}\).
Why this answer is correct
The correct answer is C. \(\frac{8+\sqrt{39}}{5}\). Multiplying by the conjugate gives numerator \(16+2\sqrt{39}\) and denominator (10). So the answer is \(\frac{8+\sqrt{39}}{5}\).
Exam Tip
संयुग्मी से गुणा करने पर अंश \(16+2\sqrt{39}\) और हर (10) मिलता है। इसलिए उत्तर \(\frac{8+\sqrt{39}}{5}\) है।
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