\(\frac{\sqrt{11}+\sqrt{6}}{\sqrt{11}-\sqrt{6}}\) का सरल रूप कौन-सा है?

Which is the simplified form of \(\frac{\sqrt{11}+\sqrt{6}}{\sqrt{11}-\sqrt{6}}\)?

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

A. \(\frac{17+2\sqrt{66}}{5}\)

Step 1

Concept

Multiplying by the conjugate gives numerator \(17+2\sqrt{66}\) and denominator (5). Rationalise the denominator and simplify.

Step 2

Why this answer is correct

The correct answer is A. \(\frac{17+2\sqrt{66}}{5}\). Multiplying by the conjugate gives numerator \(17+2\sqrt{66}\) and denominator (5). Rationalise the denominator and simplify.

Step 3

Exam Tip

संयुग्मी से गुणा करने पर अंश \(17+2\sqrt{66}\) और हर (5) मिलता है। हर को परिमेय बनाकर सरल करें।

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FAQs

Mathematics Answer, Explanation and Revision Hints

\(\frac{\sqrt{11}+\sqrt{6}}{\sqrt{11}-\sqrt{6}}\) का सरल रूप कौन-सा है? / Which is the simplified form of \(\frac{\sqrt{11}+\sqrt{6}}{\sqrt{11}-\sqrt{6}}\)?

Correct Answer: A. \(\frac{17+2\sqrt{66}}{5}\). Explanation: संयुग्मी से गुणा करने पर अंश \(17+2\sqrt{66}\) और हर (5) मिलता है। हर को परिमेय बनाकर सरल करें। / Multiplying by the conjugate gives numerator \(17+2\sqrt{66}\) and denominator (5). Rationalise the denominator and simplify.

Which concept should I revise for this Mathematics MCQ?

Multiplying by the conjugate gives numerator \(17+2\sqrt{66}\) and denominator (5). Rationalise the denominator and simplify.

What exam hint can help solve this Mathematics question?

संयुग्मी से गुणा करने पर अंश \(17+2\sqrt{66}\) और हर (5) मिलता है। हर को परिमेय बनाकर सरल करें।