\(\frac{\sqrt{11}+\sqrt{2}}{\sqrt{11}-\sqrt{2}}\) का सरल रूप कौन-सा है?

Which is the simplified form of \(\frac{\sqrt{11}+\sqrt{2}}{\sqrt{11}-\sqrt{2}}\)?

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

A. \(\frac{13+2\sqrt{22}}{9}\)

Step 1

Concept

Multiplying by the conjugate gives numerator \(13+2\sqrt{22}\) and denominator (11-2=9). So the simplified form is \(\frac{13+2\sqrt{22}}{9}\).

Step 2

Why this answer is correct

The correct answer is A. \(\frac{13+2\sqrt{22}}{9}\). Multiplying by the conjugate gives numerator \(13+2\sqrt{22}\) and denominator (11-2=9). So the simplified form is \(\frac{13+2\sqrt{22}}{9}\).

Step 3

Exam Tip

संयुग्मी से गुणा करने पर अंश \(13+2\sqrt{22}\) और हर (11-2=9) मिलता है। इसलिए सरल रूप \(\frac{13+2\sqrt{22}}{9}\) है।

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Mathematics Answer, Explanation and Revision Hints

\(\frac{\sqrt{11}+\sqrt{2}}{\sqrt{11}-\sqrt{2}}\) का सरल रूप कौन-सा है? / Which is the simplified form of \(\frac{\sqrt{11}+\sqrt{2}}{\sqrt{11}-\sqrt{2}}\)?

Correct Answer: A. \(\frac{13+2\sqrt{22}}{9}\). Explanation: संयुग्मी से गुणा करने पर अंश \(13+2\sqrt{22}\) और हर (11-2=9) मिलता है। इसलिए सरल रूप \(\frac{13+2\sqrt{22}}{9}\) है। / Multiplying by the conjugate gives numerator \(13+2\sqrt{22}\) and denominator (11-2=9). So the simplified form is \(\frac{13+2\sqrt{22}}{9}\).

Which concept should I revise for this Mathematics MCQ?

Multiplying by the conjugate gives numerator \(13+2\sqrt{22}\) and denominator (11-2=9). So the simplified form is \(\frac{13+2\sqrt{22}}{9}\).

What exam hint can help solve this Mathematics question?

संयुग्मी से गुणा करने पर अंश \(13+2\sqrt{22}\) और हर (11-2=9) मिलता है। इसलिए सरल रूप \(\frac{13+2\sqrt{22}}{9}\) है।