\(\frac{6}{\sqrt{15}-\sqrt{6}}\) का परिमेयकृत रूप कौन-सा है?
Which is the rationalised form of \(\frac{6}{\sqrt{15}-\sqrt{6}}\)?
Explanation opens after your attempt
Correct Answer
A. (\frac{2\(\sqrt{15}+\sqrt{6}\)}{3})
Concept
Multiplying by the conjugate makes the denominator (15-6=9). So (\frac{6\(\sqrt{15}+\sqrt{6}\)}{9}=\frac{2\(\sqrt{15}+\sqrt{6}\)}{3}).
Why this answer is correct
The correct answer is A. (\frac{2\(\sqrt{15}+\sqrt{6}\)}{3}). Multiplying by the conjugate makes the denominator (15-6=9). So (\frac{6\(\sqrt{15}+\sqrt{6}\)}{9}=\frac{2\(\sqrt{15}+\sqrt{6}\)}{3}).
Exam Tip
संयुग्मी से गुणा करने पर हर (15-6=9) बनता है। इसलिए (\frac{6\(\sqrt{15}+\sqrt{6}\)}{9}=\frac{2\(\sqrt{15}+\sqrt{6}\)}{3}) है।
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