\(\frac{5}{\sqrt{6}-1}\) का परिमेयकृत रूप कौन-सा है?

Which is the rationalised form of \(\frac{5}{\sqrt{6}-1}\)?

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

D. (\frac{5\(\sqrt{6}+1\)}{5})

Step 1

Concept

Multiplying by the conjugate makes the denominator (6-1=5). So the form is (\frac{5\(\sqrt{6}+1\)}{5}), that is \(\sqrt{6}+1\).

Step 2

Why this answer is correct

The correct answer is D. (\frac{5\(\sqrt{6}+1\)}{5}). Multiplying by the conjugate makes the denominator (6-1=5). So the form is (\frac{5\(\sqrt{6}+1\)}{5}), that is \(\sqrt{6}+1\).

Step 3

Exam Tip

संयुग्मी से गुणा करने पर हर (6-1=5) बनता है। इसलिए रूप (\frac{5\(\sqrt{6}+1\)}{5}), यानी \(\sqrt{6}+1\), है।

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Mathematics Answer, Explanation and Revision Hints

\(\frac{5}{\sqrt{6}-1}\) का परिमेयकृत रूप कौन-सा है? / Which is the rationalised form of \(\frac{5}{\sqrt{6}-1}\)?

Correct Answer: D. (\frac{5\(\sqrt{6}+1\)}{5}). Explanation: संयुग्मी से गुणा करने पर हर (6-1=5) बनता है। इसलिए रूप (\frac{5\(\sqrt{6}+1\)}{5}), यानी \(\sqrt{6}+1\), है। / Multiplying by the conjugate makes the denominator (6-1=5). So the form is (\frac{5\(\sqrt{6}+1\)}{5}), that is \(\sqrt{6}+1\).

Which concept should I revise for this Mathematics MCQ?

Multiplying by the conjugate makes the denominator (6-1=5). So the form is (\frac{5\(\sqrt{6}+1\)}{5}), that is \(\sqrt{6}+1\).

What exam hint can help solve this Mathematics question?

संयुग्मी से गुणा करने पर हर (6-1=5) बनता है। इसलिए रूप (\frac{5\(\sqrt{6}+1\)}{5}), यानी \(\sqrt{6}+1\), है।