\(\frac{12}{\sqrt{43}-\sqrt{31}}\) का परिमेयकृत रूप कौन-सा है?

Which is the rationalised form of \(\frac{12}{\sqrt{43}-\sqrt{31}}\)?

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

C. \(\sqrt{43}+\sqrt{31}\)

Step 1

Concept

Multiplying by the conjugate makes the denominator (43-31=12). So the answer is \(\sqrt{43}+\sqrt{31}\).

Step 2

Why this answer is correct

The correct answer is C. \(\sqrt{43}+\sqrt{31}\). Multiplying by the conjugate makes the denominator (43-31=12). So the answer is \(\sqrt{43}+\sqrt{31}\).

Step 3

Exam Tip

संयुग्मी से गुणा करने पर हर (43-31=12) बनता है। इसलिए उत्तर \(\sqrt{43}+\sqrt{31}\) है।

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Mathematics Answer, Explanation and Revision Hints

\(\frac{12}{\sqrt{43}-\sqrt{31}}\) का परिमेयकृत रूप कौन-सा है? / Which is the rationalised form of \(\frac{12}{\sqrt{43}-\sqrt{31}}\)?

Correct Answer: C. \(\sqrt{43}+\sqrt{31}\). Explanation: संयुग्मी से गुणा करने पर हर (43-31=12) बनता है। इसलिए उत्तर \(\sqrt{43}+\sqrt{31}\) है। / Multiplying by the conjugate makes the denominator (43-31=12). So the answer is \(\sqrt{43}+\sqrt{31}\).

Which concept should I revise for this Mathematics MCQ?

Multiplying by the conjugate makes the denominator (43-31=12). So the answer is \(\sqrt{43}+\sqrt{31}\).

What exam hint can help solve this Mathematics question?

संयुग्मी से गुणा करने पर हर (43-31=12) बनता है। इसलिए उत्तर \(\sqrt{43}+\sqrt{31}\) है।