समांतर श्रेणी \(25,20,15,10,\ldots\) का सामान्य पद कौन-सा है?

Which is the general term of the arithmetic progression \(25,20,15,10,\ldots\)?

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

B. \(a_n=30-5n\)

Step 1

Concept

At (n=1) it gives (25), and at (n=2) it gives (20), so \(a_n=30-5n\). In exams, check a decreasing rule with the first term.

Step 2

Why this answer is correct

The correct answer is B. \(a_n=30-5n\). At (n=1) it gives (25), and at (n=2) it gives (20), so \(a_n=30-5n\). In exams, check a decreasing rule with the first term.

Step 3

Exam Tip

(n=1) पर (25) और (n=2) पर (20) मिलता है, इसलिए \(a_n=30-5n\) है। परीक्षा में घटते नियम को पहले पद से जाँचें।

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Mathematics Answer, Explanation and Revision Hints

समांतर श्रेणी \(25,20,15,10,\ldots\) का सामान्य पद कौन-सा है? / Which is the general term of the arithmetic progression \(25,20,15,10,\ldots\)?

Correct Answer: B. \(a_n=30-5n\). Explanation: (n=1) पर (25) और (n=2) पर (20) मिलता है, इसलिए \(a_n=30-5n\) है। परीक्षा में घटते नियम को पहले पद से जाँचें। / At (n=1) it gives (25), and at (n=2) it gives (20), so \(a_n=30-5n\). In exams, check a decreasing rule with the first term.

Which concept should I revise for this Mathematics MCQ?

At (n=1) it gives (25), and at (n=2) it gives (20), so \(a_n=30-5n\). In exams, check a decreasing rule with the first term.

What exam hint can help solve this Mathematics question?

(n=1) पर (25) और (n=2) पर (20) मिलता है, इसलिए \(a_n=30-5n\) है। परीक्षा में घटते नियम को पहले पद से जाँचें।