\(\sqrt{3}\) की अपरिमेयता के प्रमाण में सही मध्य चरण कौन-सा है?
Which is the correct middle step in the proof of irrationality of \(\sqrt{3}\)?
Explanation opens after your attempt
Correct Answer
D. \(p^2=3q^2\)
Concept
Squaring \(\sqrt{3}=\frac{p}{q}\) gives \(p^2=3q^2\). This is the basis for divisibility.
Why this answer is correct
The correct answer is D. \(p^2=3q^2\). Squaring \(\sqrt{3}=\frac{p}{q}\) gives \(p^2=3q^2\). This is the basis for divisibility.
Exam Tip
\(\sqrt{3}=\frac{p}{q}\) को वर्ग करने पर \(p^2=3q^2\) मिलता है। यही आगे विभाज्यता का आधार है।
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