वर्गमूल सर्पिल में \(\sqrt{9999}\) और \(\sqrt{10000}\) की सही तुलना कौन-सी है?

Which is the correct comparison of \(\sqrt{9999}\) and \(\sqrt{10000}\) in a square root spiral?

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

A. \(\sqrt{9999}\) (99) और (100) के बीच है, \(\sqrt{10000}=100\) है\(\sqrt{9999}\) lies between (99) and (100), and \(\sqrt{10000}=100\)

Step 1

Concept

\(99^2<9999<100^2\) and \(10000=100^2\). Therefore \(\sqrt{9999}\) is slightly less than (100).

Step 2

Why this answer is correct

The correct answer is A. \(\sqrt{9999}\) (99) और (100) के बीच है, \(\sqrt{10000}=100\) है / \(\sqrt{9999}\) lies between (99) and (100), and \(\sqrt{10000}=100\). \(99^2<9999<100^2\) and \(10000=100^2\). Therefore \(\sqrt{9999}\) is slightly less than (100).

Step 3

Exam Tip

\(99^2<9999<100^2\) और \(10000=100^2\) है। इसलिए \(\sqrt{9999}\) (100) से थोड़ा कम है।

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Mathematics Answer, Explanation and Revision Hints

वर्गमूल सर्पिल में \(\sqrt{9999}\) और \(\sqrt{10000}\) की सही तुलना कौन-सी है? / Which is the correct comparison of \(\sqrt{9999}\) and \(\sqrt{10000}\) in a square root spiral?

Correct Answer: A. \(\sqrt{9999}\) (99) और (100) के बीच है, \(\sqrt{10000}=100\) है / \(\sqrt{9999}\) lies between (99) and (100), and \(\sqrt{10000}=100\). Explanation: \(99^2<9999<100^2\) और \(10000=100^2\) है। इसलिए \(\sqrt{9999}\) (100) से थोड़ा कम है। / \(99^2<9999<100^2\) and \(10000=100^2\). Therefore \(\sqrt{9999}\) is slightly less than (100).

Which concept should I revise for this Mathematics MCQ?

\(99^2<9999<100^2\) and \(10000=100^2\). Therefore \(\sqrt{9999}\) is slightly less than (100).

What exam hint can help solve this Mathematics question?

\(99^2<9999<100^2\) और \(10000=100^2\) है। इसलिए \(\sqrt{9999}\) (100) से थोड़ा कम है।