Which is the correct ascending order of 0.2, 0.0202, 0.022, and 0.202?
Answer and explanation
Correct answer: 0.0202 < 0.022 < 0.2 < 0.202
The governing concept is comparison by decimal place value. To compare fairly, write every number with four decimal places: 0.2000, 0.0202, 0.0220, and 0.2020. Reading from left to right, 0.0202 is smallest because its tenths digit is 0 and its hundredths digit is 2. Next comes 0.0220, whose thousandths digit is 2. The numbers 0.2000 and 0.2020 are larger, and 0.2020 is the greatest. Thus the ascending order is 0.0202 < 0.022 < 0.2 < 0.202, which is option A. Appending zeros does not change values; it only aligns place values for comparison.
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What is the correct answer to this question?
0.0202 < 0.022 < 0.2 < 0.202
Why is this the correct answer?
The governing concept is comparison by decimal place value. To compare fairly, write every number with four decimal places: 0.2000, 0.0202, 0.0220, and 0.2020. Reading from left to right, 0.0202 is smallest because its tenths digit is 0 and its hundredths digit is 2. Next comes 0.0220, whose thousandths digit is 2. The numbers 0.2000 and 0.2020 are larger, and 0.2020 is the greatest. Thus the ascending order is 0.0202 < 0.022 < 0.2 < 0.202, which is option A. Appending zeros does not change values; it only aligns place values for comparison.
Which subject and chapter does this question cover?
This is a Class 9 Mathematics question. Chapter: Number Systems. Topic: Decimal representation.
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