संख्या \(\sqrt{32}\) को सरल करने पर कौन-सा अपरिमेय रूप मिलता है?
Which irrational form is obtained after simplifying \(\sqrt{32}\)?
Explanation opens after your attempt
Correct Answer
C. \(4\sqrt{2}\)
Concept
\(\sqrt{32}=\sqrt{16\times2}=4\sqrt{2}\). Since \(\sqrt{2}\) remains, it is irrational.
Why this answer is correct
The correct answer is C. \(4\sqrt{2}\). \(\sqrt{32}=\sqrt{16\times2}=4\sqrt{2}\). Since \(\sqrt{2}\) remains, it is irrational.
Exam Tip
\(\sqrt{32}=\sqrt{16\times2}=4\sqrt{2}\) होता है। \(\sqrt{2}\) बचने से यह अपरिमेय है।
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