कौन-सा भिन्न असांत आवर्ती दशमलव देगा?
Which fraction gives a non-terminating recurring decimal?
Explanation opens after your attempt
Correct Answer
C. \(\frac{1}{6}\)
Concept
The denominator of \(\frac{1}{6}\) has (3), so the decimal is non-terminating recurring. Exam tip: look for factors other than (2) and (5).
Why this answer is correct
The correct answer is C. \(\frac{1}{6}\). The denominator of \(\frac{1}{6}\) has (3), so the decimal is non-terminating recurring. Exam tip: look for factors other than (2) and (5).
Exam Tip
\(\frac{1}{6}\) के हर में (3) भी है इसलिए दशमलव असांत आवर्ती होगा। परीक्षा में (2) और (5) के अलावा गुणनखंड देखें।
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