वर्गमूल सर्पिल में \(\sqrt{81}\) से \(\sqrt{82}\) बनने पर कौन-सा कथन सही है?

When \(\sqrt{82}\) is formed from \(\sqrt{81}\) in a square root spiral, which statement is correct?

Author: Muft Shiksha Editorial Team Published:
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Correct Answer

A. \(\sqrt{81}=9\) और नया कर्ण \(\sqrt{82}\) है\(\sqrt{81}=9\) and the new hypotenuse is \(\sqrt{82}\)

Step 1

Concept

\(\sqrt{81}=9\), and after adding a (1) unit perpendicular the next hypotenuse is \(\sqrt{82}\). The number increases by one.

Step 2

Why this answer is correct

The correct answer is A. \(\sqrt{81}=9\) और नया कर्ण \(\sqrt{82}\) है / \(\sqrt{81}=9\) and the new hypotenuse is \(\sqrt{82}\). \(\sqrt{81}=9\), and after adding a (1) unit perpendicular the next hypotenuse is \(\sqrt{82}\). The number increases by one.

Step 3

Exam Tip

\(\sqrt{81}=9\) है और (1) इकाई लंब जोड़ने पर अगला कर्ण \(\sqrt{82}\) बनता है। क्रम में संख्या एक बढ़ती है।

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Mathematics Answer, Explanation and Revision Hints

वर्गमूल सर्पिल में \(\sqrt{81}\) से \(\sqrt{82}\) बनने पर कौन-सा कथन सही है? / When \(\sqrt{82}\) is formed from \(\sqrt{81}\) in a square root spiral, which statement is correct?

Correct Answer: A. \(\sqrt{81}=9\) और नया कर्ण \(\sqrt{82}\) है / \(\sqrt{81}=9\) and the new hypotenuse is \(\sqrt{82}\). Explanation: \(\sqrt{81}=9\) है और (1) इकाई लंब जोड़ने पर अगला कर्ण \(\sqrt{82}\) बनता है। क्रम में संख्या एक बढ़ती है। / \(\sqrt{81}=9\), and after adding a (1) unit perpendicular the next hypotenuse is \(\sqrt{82}\). The number increases by one.

Which concept should I revise for this Mathematics MCQ?

\(\sqrt{81}=9\), and after adding a (1) unit perpendicular the next hypotenuse is \(\sqrt{82}\). The number increases by one.

What exam hint can help solve this Mathematics question?

\(\sqrt{81}=9\) है और (1) इकाई लंब जोड़ने पर अगला कर्ण \(\sqrt{82}\) बनता है। क्रम में संख्या एक बढ़ती है।