वर्गमूल सर्पिल में \(\sqrt{64}\) से \(\sqrt{65}\) बनने पर कौन-सा कथन सही है?
When \(\sqrt{65}\) is formed from \(\sqrt{64}\) in a square root spiral, which statement is correct?
Explanation opens after your attempt
A. \(\sqrt{64}=8\) और नया कर्ण \(\sqrt{65}\) है\(\sqrt{64}=8\) and the new hypotenuse is \(\sqrt{65}\)
Concept
\(\sqrt{64}=8\) is a whole number. Adding a (1) unit perpendicular forms the next hypotenuse \(\sqrt{65}\).
Why this answer is correct
The correct answer is A. \(\sqrt{64}=8\) और नया कर्ण \(\sqrt{65}\) है / \(\sqrt{64}=8\) and the new hypotenuse is \(\sqrt{65}\). \(\sqrt{64}=8\) is a whole number. Adding a (1) unit perpendicular forms the next hypotenuse \(\sqrt{65}\).
Exam Tip
\(\sqrt{64}=8\) पूर्ण संख्या है। (1) इकाई लंब जोड़ने पर अगला कर्ण \(\sqrt{65}\) बनता है।
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