वर्गमूल सर्पिल में \(\sqrt{64}\) से \(\sqrt{65}\) बनने पर कौन-सा कथन सही है?

When \(\sqrt{65}\) is formed from \(\sqrt{64}\) in a square root spiral, which statement is correct?

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

A. \(\sqrt{64}=8\) और नया कर्ण \(\sqrt{65}\) है\(\sqrt{64}=8\) and the new hypotenuse is \(\sqrt{65}\)

Step 1

Concept

\(\sqrt{64}=8\) is a whole number. Adding a (1) unit perpendicular forms the next hypotenuse \(\sqrt{65}\).

Step 2

Why this answer is correct

The correct answer is A. \(\sqrt{64}=8\) और नया कर्ण \(\sqrt{65}\) है / \(\sqrt{64}=8\) and the new hypotenuse is \(\sqrt{65}\). \(\sqrt{64}=8\) is a whole number. Adding a (1) unit perpendicular forms the next hypotenuse \(\sqrt{65}\).

Step 3

Exam Tip

\(\sqrt{64}=8\) पूर्ण संख्या है। (1) इकाई लंब जोड़ने पर अगला कर्ण \(\sqrt{65}\) बनता है।

Question me issue ya doubt hai?

Answer, explanation, typing mistake ya suggestion directly hamari team ko bhejein. 📱Helpline (Call / WhatsApp): +91 7272824365

Related Mathematics Questions

FAQs

Mathematics Answer, Explanation and Revision Hints

वर्गमूल सर्पिल में \(\sqrt{64}\) से \(\sqrt{65}\) बनने पर कौन-सा कथन सही है? / When \(\sqrt{65}\) is formed from \(\sqrt{64}\) in a square root spiral, which statement is correct?

Correct Answer: A. \(\sqrt{64}=8\) और नया कर्ण \(\sqrt{65}\) है / \(\sqrt{64}=8\) and the new hypotenuse is \(\sqrt{65}\). Explanation: \(\sqrt{64}=8\) पूर्ण संख्या है। (1) इकाई लंब जोड़ने पर अगला कर्ण \(\sqrt{65}\) बनता है। / \(\sqrt{64}=8\) is a whole number. Adding a (1) unit perpendicular forms the next hypotenuse \(\sqrt{65}\).

Which concept should I revise for this Mathematics MCQ?

\(\sqrt{64}=8\) is a whole number. Adding a (1) unit perpendicular forms the next hypotenuse \(\sqrt{65}\).

What exam hint can help solve this Mathematics question?

\(\sqrt{64}=8\) पूर्ण संख्या है। (1) इकाई लंब जोड़ने पर अगला कर्ण \(\sqrt{65}\) बनता है।