\(3+\sqrt{2}\) किस प्रकार की संख्या है?

What type of number is \(3+\sqrt{2}\)?

Explanation opens after your attempt
Correct Answer

B. अपरिमेय वास्तविक संख्याIrrational real number

Step 1

Concept

Adding the irrational \( \sqrt{2} \) to the rational number (3) generally gives an irrational number. It is also real.

Step 2

Why this answer is correct

The correct answer is B. अपरिमेय वास्तविक संख्या / Irrational real number. Adding the irrational \( \sqrt{2} \) to the rational number (3) generally gives an irrational number. It is also real.

Step 3

Exam Tip

परिमेय संख्या (3) में अपरिमेय \( \sqrt{2} \) जोड़ने पर सामान्यतः अपरिमेय संख्या मिलती है। यह वास्तविक संख्या भी है।

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Mathematics Answer, Explanation and Revision Hints

\(3+\sqrt{2}\) किस प्रकार की संख्या है? / What type of number is \(3+\sqrt{2}\)?

Correct Answer: B. अपरिमेय वास्तविक संख्या / Irrational real number. Explanation: परिमेय संख्या (3) में अपरिमेय \( \sqrt{2} \) जोड़ने पर सामान्यतः अपरिमेय संख्या मिलती है। यह वास्तविक संख्या भी है। / Adding the irrational \( \sqrt{2} \) to the rational number (3) generally gives an irrational number. It is also real.

Which concept should I revise for this Mathematics MCQ?

Adding the irrational \( \sqrt{2} \) to the rational number (3) generally gives an irrational number. It is also real.

What exam hint can help solve this Mathematics question?

परिमेय संख्या (3) में अपरिमेय \( \sqrt{2} \) जोड़ने पर सामान्यतः अपरिमेय संख्या मिलती है। यह वास्तविक संख्या भी है।