( \sqrt{(a-b)2} ) का मान वास्तविक संख्याओं में क्या होता है?
What is the value of ( \sqrt{(a-b)2} ) in real numbers?
Explanation opens after your attempt
Correct Answer
C. ( |a-b| )
Concept
The principal square root is always non-negative. Therefore ( \sqrt{(a-b)2}=|a-b| ).
Why this answer is correct
The correct answer is C. ( |a-b| ). The principal square root is always non-negative. Therefore ( \sqrt{(a-b)2}=|a-b| ).
Exam Tip
मुख्य वर्गमूल हमेशा गैर-ऋणात्मक होता है। इसलिए ( \sqrt{(a-b)2}=|a-b| ) होता है।
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