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What is the value of \(\left|\sqrt{36}-\sqrt{121}\right|\)?

Answer and explanation

Correct answer: 5

\(\sqrt{36}=6\) and \(\sqrt{121}=11\). Therefore, \(\sqrt{36}-\sqrt{121}=6-11=-5\). The absolute value of a number is never negative, so \(\left|-5\right|=5\). Option C is a close distractor because it is the value before applying the absolute value. Exam tip: evaluate the square roots first, then take the absolute value of the difference.

Related tags

Real NumbersAbsolute ValueSquare RootsNumber SystemsMathematicsClass 9 Mcq

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