\(\frac{\sqrt{98}-\sqrt{50}}{\sqrt{2}}\) का मान क्या है?
What is the value of \(\frac{\sqrt{98}-\sqrt{50}}{\sqrt{2}}\)?
Explanation opens after your attempt
B. (2)
Concept
\(\sqrt{98}=7\sqrt{2}\) and \(\sqrt{50}=5\sqrt{2}\), so the numerator is \(2\sqrt{2}\). Dividing gives (2).
Why this answer is correct
The correct answer is B. (2). \(\sqrt{98}=7\sqrt{2}\) and \(\sqrt{50}=5\sqrt{2}\), so the numerator is \(2\sqrt{2}\). Dividing gives (2).
Exam Tip
\(\sqrt{98}=7\sqrt{2}\) और \(\sqrt{50}=5\sqrt{2}\), इसलिए अंश \(2\sqrt{2}\) है। भाग देने पर (2) मिलता है।
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