\(\frac{\sqrt{98}-\sqrt{50}}{\sqrt{2}}\) का मान क्या है?

What is the value of \(\frac{\sqrt{98}-\sqrt{50}}{\sqrt{2}}\)?

Author: Muft Shiksha Editorial Team Published:
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Correct Answer

B. (2)

Step 1

Concept

\(\sqrt{98}=7\sqrt{2}\) and \(\sqrt{50}=5\sqrt{2}\), so the numerator is \(2\sqrt{2}\). Dividing gives (2).

Step 2

Why this answer is correct

The correct answer is B. (2). \(\sqrt{98}=7\sqrt{2}\) and \(\sqrt{50}=5\sqrt{2}\), so the numerator is \(2\sqrt{2}\). Dividing gives (2).

Step 3

Exam Tip

\(\sqrt{98}=7\sqrt{2}\) और \(\sqrt{50}=5\sqrt{2}\), इसलिए अंश \(2\sqrt{2}\) है। भाग देने पर (2) मिलता है।

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FAQs

Mathematics Answer, Explanation and Revision Hints

\(\frac{\sqrt{98}-\sqrt{50}}{\sqrt{2}}\) का मान क्या है? / What is the value of \(\frac{\sqrt{98}-\sqrt{50}}{\sqrt{2}}\)?

Correct Answer: B. (2). Explanation: \(\sqrt{98}=7\sqrt{2}\) और \(\sqrt{50}=5\sqrt{2}\), इसलिए अंश \(2\sqrt{2}\) है। भाग देने पर (2) मिलता है। / \(\sqrt{98}=7\sqrt{2}\) and \(\sqrt{50}=5\sqrt{2}\), so the numerator is \(2\sqrt{2}\). Dividing gives (2).

Which concept should I revise for this Mathematics MCQ?

\(\sqrt{98}=7\sqrt{2}\) and \(\sqrt{50}=5\sqrt{2}\), so the numerator is \(2\sqrt{2}\). Dividing gives (2).

What exam hint can help solve this Mathematics question?

\(\sqrt{98}=7\sqrt{2}\) और \(\sqrt{50}=5\sqrt{2}\), इसलिए अंश \(2\sqrt{2}\) है। भाग देने पर (2) मिलता है।