\(\frac{\sqrt{392}+\sqrt{200}}{\sqrt{2}}\) का मान क्या है?

What is the value of \(\frac{\sqrt{392}+\sqrt{200}}{\sqrt{2}}\)?

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

C. (24)

Step 1

Concept

\(\sqrt{392}=14\sqrt{2}\) and \(\sqrt{200}=10\sqrt{2}\), so the numerator is \(24\sqrt{2}\). Dividing gives (24).

Step 2

Why this answer is correct

The correct answer is C. (24). \(\sqrt{392}=14\sqrt{2}\) and \(\sqrt{200}=10\sqrt{2}\), so the numerator is \(24\sqrt{2}\). Dividing gives (24).

Step 3

Exam Tip

\(\sqrt{392}=14\sqrt{2}\) और \(\sqrt{200}=10\sqrt{2}\), इसलिए अंश \(24\sqrt{2}\) है। भाग देने पर (24) मिलता है।

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FAQs

Mathematics Answer, Explanation and Revision Hints

\(\frac{\sqrt{392}+\sqrt{200}}{\sqrt{2}}\) का मान क्या है? / What is the value of \(\frac{\sqrt{392}+\sqrt{200}}{\sqrt{2}}\)?

Correct Answer: C. (24). Explanation: \(\sqrt{392}=14\sqrt{2}\) और \(\sqrt{200}=10\sqrt{2}\), इसलिए अंश \(24\sqrt{2}\) है। भाग देने पर (24) मिलता है। / \(\sqrt{392}=14\sqrt{2}\) and \(\sqrt{200}=10\sqrt{2}\), so the numerator is \(24\sqrt{2}\). Dividing gives (24).

Which concept should I revise for this Mathematics MCQ?

\(\sqrt{392}=14\sqrt{2}\) and \(\sqrt{200}=10\sqrt{2}\), so the numerator is \(24\sqrt{2}\). Dividing gives (24).

What exam hint can help solve this Mathematics question?

\(\sqrt{392}=14\sqrt{2}\) और \(\sqrt{200}=10\sqrt{2}\), इसलिए अंश \(24\sqrt{2}\) है। भाग देने पर (24) मिलता है।