\(\frac{\sqrt{18}+\sqrt{72}}{\sqrt{2}}\) का मान क्या है?
What is the value of \(\frac{\sqrt{18}+\sqrt{72}}{\sqrt{2}}\)?
Explanation opens after your attempt
Correct Answer
B. (9)
Concept
\(\sqrt{18}=3\sqrt{2}\) and \(\sqrt{72}=6\sqrt{2}\) so the numerator is \(9\sqrt{2}\). Dividing by \(\sqrt{2}\) gives (9).
Why this answer is correct
The correct answer is B. (9). \(\sqrt{18}=3\sqrt{2}\) and \(\sqrt{72}=6\sqrt{2}\) so the numerator is \(9\sqrt{2}\). Dividing by \(\sqrt{2}\) gives (9).
Exam Tip
\(\sqrt{18}=3\sqrt{2}\) और \(\sqrt{72}=6\sqrt{2}\) है इसलिए अंश \(9\sqrt{2}\) है। \(\sqrt{2}\) से भाग देने पर (9) मिलता है।
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