\(\frac{1}{\sqrt{8}+\sqrt{6}}+\frac{1}{\sqrt{8}-\sqrt{6}}\) का मान क्या है?
What is the value of \(\frac{1}{\sqrt{8}+\sqrt{6}}+\frac{1}{\sqrt{8}-\sqrt{6}}\)?
Explanation opens after your attempt
Correct Answer
A. \(2\sqrt{8}\)
Concept
The first term becomes \(\frac{\sqrt{8}-\sqrt{6}}{2}\) and the second becomes \(\frac{\sqrt{8}+\sqrt{6}}{2}\). Their sum is \(\sqrt{8}\).
Why this answer is correct
The correct answer is A. \(2\sqrt{8}\). The first term becomes \(\frac{\sqrt{8}-\sqrt{6}}{2}\) and the second becomes \(\frac{\sqrt{8}+\sqrt{6}}{2}\). Their sum is \(\sqrt{8}\).
Exam Tip
पहला पद \(\frac{\sqrt{8}-\sqrt{6}}{2}\) और दूसरा \(\frac{\sqrt{8}+\sqrt{6}}{2}\) बनता है। योग \(\sqrt{8}\) है।
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