\(\frac{1}{\sqrt{3}+\sqrt{2}}+\frac{1}{\sqrt{3}-\sqrt{2}}\) का मान क्या है?

What is the value of \(\frac{1}{\sqrt{3}+\sqrt{2}}+\frac{1}{\sqrt{3}-\sqrt{2}}\)?

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

A. \(2\sqrt{3}\)

Step 1

Concept

The first term becomes \(\sqrt{3}-\sqrt{2}\) and the second becomes \(\sqrt{3}+\sqrt{2}\). Their sum is \(2\sqrt{3}\).

Step 2

Why this answer is correct

The correct answer is A. \(2\sqrt{3}\). The first term becomes \(\sqrt{3}-\sqrt{2}\) and the second becomes \(\sqrt{3}+\sqrt{2}\). Their sum is \(2\sqrt{3}\).

Step 3

Exam Tip

पहला पद \(\sqrt{3}-\sqrt{2}\) और दूसरा \(\sqrt{3}+\sqrt{2}\) बनता है। योग \(2\sqrt{3}\) है।

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FAQs

Mathematics Answer, Explanation and Revision Hints

\(\frac{1}{\sqrt{3}+\sqrt{2}}+\frac{1}{\sqrt{3}-\sqrt{2}}\) का मान क्या है? / What is the value of \(\frac{1}{\sqrt{3}+\sqrt{2}}+\frac{1}{\sqrt{3}-\sqrt{2}}\)?

Correct Answer: A. \(2\sqrt{3}\). Explanation: पहला पद \(\sqrt{3}-\sqrt{2}\) और दूसरा \(\sqrt{3}+\sqrt{2}\) बनता है। योग \(2\sqrt{3}\) है। / The first term becomes \(\sqrt{3}-\sqrt{2}\) and the second becomes \(\sqrt{3}+\sqrt{2}\). Their sum is \(2\sqrt{3}\).

Which concept should I revise for this Mathematics MCQ?

The first term becomes \(\sqrt{3}-\sqrt{2}\) and the second becomes \(\sqrt{3}+\sqrt{2}\). Their sum is \(2\sqrt{3}\).

What exam hint can help solve this Mathematics question?

पहला पद \(\sqrt{3}-\sqrt{2}\) और दूसरा \(\sqrt{3}+\sqrt{2}\) बनता है। योग \(2\sqrt{3}\) है।