बहुपद \(x^6y^3z^4+4x^2y^2z^9-12\) की कुल डिग्री क्या है?

What is the total degree of \(x^6y^3z^4+4x^2y^2z^9-12\)?

Author: Muft Shiksha Editorial Team Published:
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Correct Answer

A. (13)

Step 1

Concept

The total power of the first term is (6+3+4=13) and of the second term is (2+2+9=13). Therefore the total degree is (13).

Step 2

Why this answer is correct

The correct answer is A. (13). The total power of the first term is (6+3+4=13) and of the second term is (2+2+9=13). Therefore the total degree is (13).

Step 3

Exam Tip

पहले पद की कुल घात (6+3+4=13) है और दूसरे पद की (2+2+9=13) है। इसलिए कुल डिग्री (13) है।

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Mathematics Answer, Explanation and Revision Hints

बहुपद \(x^6y^3z^4+4x^2y^2z^9-12\) की कुल डिग्री क्या है? / What is the total degree of \(x^6y^3z^4+4x^2y^2z^9-12\)?

Correct Answer: A. (13). Explanation: पहले पद की कुल घात (6+3+4=13) है और दूसरे पद की (2+2+9=13) है। इसलिए कुल डिग्री (13) है। / The total power of the first term is (6+3+4=13) and of the second term is (2+2+9=13). Therefore the total degree is (13).

Which concept should I revise for this Mathematics MCQ?

The total power of the first term is (6+3+4=13) and of the second term is (2+2+9=13). Therefore the total degree is (13).

What exam hint can help solve this Mathematics question?

पहले पद की कुल घात (6+3+4=13) है और दूसरे पद की (2+2+9=13) है। इसलिए कुल डिग्री (13) है।