गुणोत्तर श्रेढ़ी \(12,6,3,\frac{3}{2},\ldots\) के पहले (5) पदों का योग क्या है?
What is the sum of the first (5) terms of the geometric progression \(12,6,3,\frac{3}{2},\ldots\)?
Explanation opens after your attempt
Correct Answer
B. \(\frac{93}{4}\)
Concept
The first (5) terms are \(12,6,3,\frac{3}{2},\frac{3}{4}\), and their sum is \(\frac{93}{4}\). Add fractional terms using a common denominator.
Why this answer is correct
The correct answer is B. \(\frac{93}{4}\). The first (5) terms are \(12,6,3,\frac{3}{2},\frac{3}{4}\), and their sum is \(\frac{93}{4}\). Add fractional terms using a common denominator.
Exam Tip
पहले (5) पद \(12,6,3,\frac{3}{2},\frac{3}{4}\) हैं और योग \(\frac{93}{4}\) है। भिन्न पदों को समान हर से जोड़ें।
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