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What is the sum of the first (5) terms of the geometric progression (12,6,3,\frac{3}{2},\ldots)?गुणोत्तर श्रेढ़ी (12,6,3,\frac{3}{2},\ldots) के पहले (5) पदों का योग क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (\frac{93}{4})(\frac{93}{4})
The first (5) terms are (12,6,3,\frac{3}{2},\frac{3}{4}), and their sum is (\frac{93}{4}). Add fractional terms using a common denominator.पहले (5) पद (12,6,3,\frac{3}{2},\frac{3}{4}) हैं और योग (\frac{93}{4}) है। भिन्न पदों को समान हर से जोड़ें।
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